The problem here:
2. In eight tosses of a fair coin, find the probability that heads will come up
(a) exactly three times;
(b) at least three times;
(c) at most three times.
Answers:
A)
To solve this part i used next formula:
Where:
- "k" is the number of hits.
- "n" is the number of trials.
- "p" is the probability of success
B)
To solve this part i used next formula
- "k" is the number of hits.
- "n" is the number of trials.
- "p" is the probability of succes
- "u" is the exactly k succes (sigma)
now resolve:
=
=
and the result is: 2.2226
C)
To resolve this part i used the next formula:
Where:
- P is probability of the event,
- C (n, k) are combinations of k elements from n elements a total
- p is the probability of success and q = (1-p) the probability of failure
- n number of times to repeat the individual case
- k number of successes
and the result is:1/256
Lo de A está bien; "exactly three times" = distribución binomial.
ResponderEliminarEn B, "at least three times", podrías sumar las distribuciones binomiales para k = 3, 4, 5, 6, 7, 8. Mientras "C" sería at most three times 1 - suma de binomiales de 0, 1, 2 y 3 ;)
Van 2 pts extra. Tu respuesta de B está muy obviamente equivocada; debería ser una probabiidad y está encima de uno ;)